What is the difference between solid, liquid and ice? Use ice, water and steam as examples.

Answers

Answer 1

Answer:

Answer: A solid is something that can hold its own shape and is hard to compress (squash). However, ice is different from most solids because its molecules are less densely packed than in liquid water so ice takes up a little more space than the same amount of liquid water. This is why ice floats.

Explanation: Hope it works!!!!!

Related Questions

Water flows over Niagara Falss at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing that the graviatational potential energy of falling water per second = mass (kg) x height (m) x gravity (9.8 m/s2), what is the power of Niagara Falls? How many 15 W LED light bulbs could it power?
Chloride is nearly twice the size of chlorine even though it only gains one electron. Explain why.
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
How much energy (in J) is lost when a sample of iron with a mass of 26.4 g cools from 74.0 ∘C to 26.0 ∘C?
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The amount of I − 3 ( aq ) in a solution can be determined by titration with a solution containing a known concentration of S 2 O 2 − 3 ( aq ) (thiosulfate ion). The determination is based on the net ionic equation 2 S 2 O 2 − 3 ( aq ) + I − 3 ( aq ) ⟶ S 4 O 2 − 6 ( aq ) + 3 I − ( aq ) Given that it requires 29.4 mL of 0.380 M Na 2 S 2 O 3 ( aq ) to titrate a 30.0 mL sample of I − 3 ( aq ) , calculate the molarity of I − 3 ( aq ) in the solution.

Answers

Answer:

The molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Explanation:

Given net ionic equation:

2S₂O₃²⁻ (aq) + I₃⁻ ( aq ) ⟶ S₄O₆²⁻ (aq) + 3I⁻ (aq)

Number of moles of S₂O₃²⁻: n₁ = 2, Number of moles of I₃⁻: n₂ = 1

Given- For S₂O₃²⁻ solution: Molarity: M₁ = 0.380 M, Volume: V₁ = 29.4 mL;

For I₃⁻ (aq) solution: Molarity: M₂ = ? M, Volume: V₂ = 30.0 mL

To calculate the molarity of I₃⁻ (aq) solution, we use the equation:

$(M_(1)V_(1))/(n_(1))=(M_(2)V_(2))/(n_(2))$

$((0.380 M)* (29.4 mL))/(2)=(M_(2)* (30.0 mL))/(1)$

$\Rightarrow M_(2) = ((0.380 M)* (29.4 mL))/((30.0 mL)* 2) = 0.186 M$

Therefore, the molarity of I₃⁻ (aq) solution: M₂ = 0.186 M

Which one of these anions would have an "ic" ending as an acid?(FO3)-1
Br-1
(NO3)-1
(SO3)2

Answers

the (so3)2hope this help

The so32 hope this help

Which of the following atoms could have an expanded octet when it is the central atom in a covalent compound?a) Bb) O
c) Cl
d) F

Answers

Answer:

only chlorine can expand its octet.

Explanation:

An atom can expand its octet is it has empty d orbital

the electronic configuration of given elements will be:

B : 1s2 2s2 2p1 [Valence shell n =2 no d orbital]

O :1s2 2s2 2p4 [Valence shell n =2 no d orbital]

F : 1s2 2s2 2p5 [Valence shell n =2 no d orbital]

Cl :1s2 2s2 2p6 3s2 3p5 3d0 [Valence shell n =2 no d orbital]

Out of given elements only chlorine has empty d orbitals in its valence shell

Thus only chlorine can expand its octet.

What is the mass, in grams, of 1.50 mol of iron (III) sulfate?Express your answer using three significant figures.

Answers

Answer : The mass of 1.50 mole of iron(III) sulfate is, $5.99* 10^2g$

Explanation : Given,

Moles of iron(III) sulfate = 1.50 mole

Molar mass of iron(III) sulfate = 399.88 g/mole

The formula of iron(III) sulfate is, $Fe_2(SO_4)_3$

Formula used :

$\text{Mass of }Fe_2(SO_4)_3=\text{Moles of }Fe_2(SO_4)_3* \text{Molar mass of }Fe_2(SO_4)_3$

Now put all the given values in this formula, we get:

$\text{Mass of }Fe_2(SO_4)_3=1.50mole* 399.88g/mole$

$\text{Mass of }Fe_2(SO_4)_3=599.82g=5.99* 10^2g$

Therefore, the mass of 1.50 mole of iron(III) sulfate is, $5.99* 10^2g$

What would cause the percent yield of a reaction to be less than 100%?All of the limiting reagent gets used up.

The product participates in a side reaction.

Pure reactants are used.

A balanced chemical equation is used.

Answers

The product participates in a side reaction.

Explanation:

The reason why percentage yield for a chemical reaction can be less than a 100% is due to the presence of competing side reactions. As often the case and basics for all chemical reactions, mass and matter must be conserved. But sometimes the yield can be lower due to other reactions that must be considered.

A competing side reaction that can affect the yield of products during a chemical procedure is often one in which some of the products can react with some molecules present in the environment or some of the unused reactants when available.
Sometimes, a product can be hygroscopic, deliquescent or probably effervescent. This will definitely alter the expected amount of product one desires in a reaction based on stoichiometry.

Learn More:

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Answer:

The product participates in a side reaction.

Explanation:

If the heat of combustion of carbon monoxide (CO) is −283.0 kJmole, how many grams of carbon monoxide must combust in order to release 2,500.kJ of energy?

Answers

Answer:

247.4 g

Explanation:

Let's consider the thermochemical equation for the combustion of carbon monoxide.

CO(g) + 0.5 O₂(g) ⇒ CO₂(g) ΔH°c = -283.0 kJ/mol

The moles of carbon monoxide required to release 2500 kJ (-2500 kJ) are:

-2500 kJ × (1 mol CO/-283.0 kJ) = 8.834 mol CO

The molar mass of CO is 28.01 g/mol. The mass corresponding to 8.834 moles of CO is:

8.834 mol × 28.01 g/mol = 247.4 g

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