Plants make their own food through a process called ____________.(6th grade science)

Answers

Answer 1
Answer:

Answer:

Photosynthesis

Explanation:

Answer 2
Answer:

Question:

Plants make their own food through a process called ____________.(6th grade science)

Answer:

The correct answer to the blank is photosynthesis. Photosynthesis is the process that enables plants to get energy from the sun. Light energy from the sun is converted into chemical energy by chlorophyll. Chlorophyll gives plants their green color.

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The material the start all reactions are ______ and the materials that are formed are called _____.

Answers

Reactant and then product

Answer:

I think the second space is chemical bonds

If 4.0 mol aluminum and 7.0 mol hydrogen bromide react according to the following equation, how many moles of hydrogen are formed and what is the limiting reactant?

Answers

Answer:

Moles of hydrogen formed = 3.5 moles

Explanation:

Given that:-

Moles of aluminium= 4.0 mol

Moles of hydrogen bromide = 7.0 mol

According to the reaction:-

2Al_((s))+6HBr_((aq))\rightarrow 2AlBr_3_((aq))+3H_2_((g))

2 moles of aluminum react with 6 moles of hydrogen bromide

1 mole of aluminum react with 6/2 moles of hydrogen bromide

4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide

Moles of hydrogen bromide = 12 moles

Available moles of hydrogen bromide = 7.0 moles

Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)

The formation of the product is governed by the limiting reagent. So,

6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen

1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen

7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen

Moles of hydrogen formed = 3.5 moles

Answer:

3.5 mol H2, HBr (limiting reactant)

Explanation:

4.0 mol Al × 3 mol H2/ 2 mol Al = 6.0 mol H2

7.0 mol HB ×3 mol H2/ 6mol HBr = 3.5 mol H2

Since 7.0mol of HBr will produce less H2 than 4.0mol of Al, HBr will be the limiting reactant, and the reaction will produce 3.5mol of H2.

A Carbon-10 nucleus has 6 protons and 4 neutrons. Through radioactive beta decay, it turns into a Boron-10 nucleus, with 5 protons and 5 neutrons, plus another particle. What kind of additional particle, if any, is produced during this decay

Answers

Answer:

No additional particle was produced during the decay.

Explanation:

The equation of decay is given as;

¹⁰₆C  + ⁰₋₁ e → ¹⁰₅B + x

To identify x, we have to calculate its atomic and mass number.

In the reactants side;

Atomic Number = 6 + (-1) = 5

Mass number = 10 + 0 = 10

In the products side;

Atomic Number = 5 + x

Mass Number = 10 + x

Generally, reactant = product

Atomic Number;

5 = 5 + x

x = 5 - 5 = 0

Mass Number;

10 = 10 + x

x = 10 - 10 = 0

This means no additional particle was produced during the decay.

Which of the following chemicals is potentially dangerous?A. ammonium nitrate

B. ethyl alcohol

C.sulfuric acid

D.All chemicals are potentially dangerous

Answers

Answer:

D.All chemicals are potentially dangerous

Explanation:

No chemical is toxicologically neutral

The density of an element is 11.3 g/cm'. What is its density in kg/mº? ​

Answers

The density of the element in grams per cubic centimeter can be rewritten in kilograms per cubic meter as 11,300 kg/m³

What is the density of the element in kilograms per cubic meter?

Given the parameter:

The density of an element is 11.3 g/cm³

To convert the density from grams per cubic centimeter to kilograms per cubic meter, we can use the following conversion factors:

1 gram = 0.001 kilograms

1 cm³ = 1000000m³

Density in kg/m³ = Density in g/cm³ × (0.001 kg/g) × ( 1000000 m³/cm³)

Density in kg/m³ = 1000

Now, given the density of the element as 11.3 g/cm³:

Density in kg/m³ = 11.3 × 1000

Density in kg/m³ = 11,300 kg/m³

Therefore, the density of the element is approximately 11,300 kg/m³.

Learn more about density here: brainly.com/question/952755

#SPJ3

Answer:

11.3 g/cm³ = 11.3x100x100x100/ 1000 = 11300kg/m³

Explanation:

Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3 )2 as (P NH3)2. If either the numerator or denominator is 1, please enter 1 2 MoO3(s) ↔ 2 MoO2(s) + O2(g)

Answers

The expression  for the equilibrium constant Kp for the following reaction is  K_p = (po_2)

Equilibrium constant:

It refers to the ratio of the concentration of products to the concentration of reactants where each raised to the power of their stoichiometric ratios. It is expressed as K.

Since the given expression is

MoO3(s) ↔ 2 MoO2(s) + O2(g)

So, the above expression should be considered for constant kp

Learn more about reaction here; brainly.com/question/24185208

Answer: K_p={(p_(O_2))}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K

K_p is the constant of a certain reaction at equilibrium for gaseous reactants and products.

For the given chemical reaction:

MoO_3(s)\rightleftharpoons 2MoO_2(s)+O_2(g)

The expression of  for above equation follows:

K_p={(p_(O_2))}

As solids do not exert pressure, MoO_3 and MoO_2  are not involved.