Focus groupsA. are usually composed of 10 to 15 people as participants
B. yield results that are largely dependent on the viewpoint of the researcher
C. always do a good job of representing the broader target market
D. have a low cost per participant

Answers

Answer 1
Answer: I think the answer is a

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Erica (39 kg ) and Danny (46 kg ) are bouncing on a trampoline. Just as Erica reaches the high point of her bounce, Danny is moving upward past her at 4.6 m/s . At that instant he grabs hold of her.
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All of the following are true of models except

Answers

I did this.
If your answers look like this... 
a. models have the ability to communicate 
b. models have the ability to correctly predict all outcomes 
c. model have the ability to test predictions
d. models have the ability to save time 
Then it's D

Final answer:

Models are representations that help us understand and analyze real-life situations, but they may have limitations or assumptions that make some statements not universally true.

Explanation:

Models are representations of real-life situations or things that help us understand and analyze them better. However, the statement, 'all of the following are true of models except,' implies that there are some characteristics that do not apply to models. Different models may have different purposes, limitations, or assumptions that may make some statements not universally true. For example, while models can provide insights and predictions, they cannot capture the full complexity of the real world or account for all variables. Models are valuable tools in various fields and disciplines, including social studies, as they help us simplify, analyze, and communicate complex phenomena and processes.

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When light falls on a soap bubble or on the oily film spread on a water puddle, a spectrum of colors is observed. How is this spectrum of colors formed? 1) separation of white light by a prism 2) absorption of colors in a pigment present 3) constructive and destructive interference of light waves 4) reflection of light by soap bubble or oil film

Answers

Answer:

Option 3) Constructive And destructive interference of light waves

Explanation:

When the light is incident on a soap bubble of certain thickness it constructively interferes for wavefronts which are in phase to produce white light and when the wavefronts are out of phase, they undergo destructive interference to produce a series of colors. Thus, interference is the reason.

Suppose you hit a 0.058-kg tennis ball so that the ball then moves with an acceleration of 10 m/s2. if you were to hit a basketball of mass 0.58 kg with the same force, what would the acceleration a of the basketball be? *graph is 4/x if that helps.

Answers

In this problem, the working equation to be used is the Newton's 2nd law of motion: Force = mass x acceleration. 


First situation: mass = 0.058 kg; acceleration = 10 m/s2

Hence, force is 0.058 kg x 10 m/s2, which is 0.58 N. Since same force is to be used, this same value is used for the second situation.

Second situation: mass = 0.58 kg; Force = 0.58 N

Since F = ma, by transposing, the acceleration could be solved by the equation, a = F/m. Thus, 0.58N/0.58 kg, the acceleration is 1 m/s2.



An small asteroid with a mass of 6.25 x 1014 kg (almost 10 billion times less mass than the Earth) creates a force of 360 N on a nearby spacecraft that has a mass of 7.20 x 105 kg, how far apart are these two objects in km?

Answers

The Objects separated by gravitational force of 360 N, masses 6.25 × 10¹⁴ kg and 7.20 × 10⁵ kg. Applying Newton's law with G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² yields distance is 2.79139 km.

We can apply Newton's law of universal gravitation to calculate the distance between the two objects. The formula takes the form:

F = (G ⋅ m₁ ⋅ m₂) / r²

Where:

F represents the force between the two objects

G stands for the gravitational constant (6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²)

m₁ and m₂ denote the masses of the two objects

r indicates the distance between the centers of the two objects

Given that the force F = 360 N, m₁ = 6.25 × 10¹⁴ kg, and m₂ = 7.20 × 10⁵ kg, we can solve for r:

r² = (G ⋅ m₁ ⋅ m₂) / F

r = √((G ⋅ m₁ ⋅ m₂) / F)

Now, substituting the values and solving for r:

r = √(((6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²) ⋅ (6.25 × 10¹⁴ kg) ⋅ (7.20 × 10⁵ kg)) / 360 N)

r ≈ 2791.39 m

Finally, converting the distance from meters to kilometers:

r ≈ 2.79139 km

Consequently, the two objects are approximately 2.79139 kilometers apart.

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The distance between the asteroid and the spacecraft is 2.3 km.

If you push on a wall with a force of 200n with what force does the wall push back

Answers

According to Newtons law, every action has an equal and opposite reaction. So if a student is pushing a wall with a force of 200n, then the wall is pushing the student with 200n 

Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.

Answers

Answer:

1.1 x 10⁵m/s²

Explanation:

Given parameters:

Velocity  = 452m/s

distance  = 0.93m

Unknown:

Acceleration of the bullet  = ?

Solution:

To solve this problem, we use one of the kinematics equation which is given below:

           V² = U²  + 2aS

V is the final velocity

U is the initial velocity  = 0m/s

a is the unknown acceleration

S is the distance traveled  

 So;

          452²   = 0²  + (2 x a x 0.93)

          204304  = 1.86a

               a  = 1.1 x 10⁵m/s²

Final answer:

The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.

Explanation:

The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).

Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.

So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.

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