Answer:
The truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.
Explanation:
The distance that the truck starts slowing down = 80 ft from the stop sign
Using equations of motion, we can calculate the distance it will take the truck to stop, then check of it is less than or more than 80 ft.
u = initial velocity of the truck = 40 mph = 58.667 ft/s
v = final velocity of the truck = 0 ft/s (since it comes to a stop eventually)
x = horizontal distance covered during the deceleration
a = Deceleration = -12 ft/s² (it'll have a negative sign, since it is negative acceleration
v² = u² + 2ax
0² = 58.667² + 2(-12)(x)
24x = 3441.816889
x = 143.41 ft
143.41 ft > 80 ft; hence, the truck will not stop in time. The truck passes the stop sign by about 63.41 ft before it stops.
A truck traveling at 40 mph is approaching a stop sign. At time t₀ and at a distance of 80 ft, the truck begins to slow down by decelerating at 12 ft/s2, will the truck be able to stop in time?
The truck will not be able to stop in time.
==> First lets convert all variables to SI units
1 mph = 0.45m/s
40mph = 40 miles per hour = 40 x 0.45 m/s
40mph = 18m/s
1 ft = 0.3048m
80 ft = 80 x 0.3048m
80 ft = 24.38m
Also;
12ft/s² = 12 x 0.3048m/s²
12ft/s² = 3.66m/s²
==> Now, consider one of the equations of motion as follows;
v² = u² + 2as -----------------(i)
Where;
v = final velocity of motion
u = initial velocity of motion
a= acceleration/deceleration of motion
s = distance covered during motion
Using this equation, lets calculate the distance, s, covered during the acceleration;
We know that;
v = 0 [since the truck comes to a stop]
u = 40mph = 18m/s
a = -12ft/s² = -3.66m/s² [the negative sign shows that the truck decelerates]
Substitute these values into equation (i) as follows;
0² = 18² + 2 (-3.66)s
0 = 324 - 7.32s
7.32s = 324
s =
s = 44.26m
The distance from where the truck starts decelerating to where it eventually stops is 44.26m which is past the stop sign (which is at 80ft = 24.38m). This means that the truck stops, 44.26m - 24.38m = 19.88m, after the stop sign. Therefore, the truck will not be able to stop in time.
Answer:
Decrease to typical from utilizing lambda-decrease:
The given lambda - math terms is, (λf.λx.f(f(fx)))(λy.y×3)2
The of taking the terms is significant in lambda - math,
For the term, (λy, y×3)2, we can substitute the incentive to the capacity.
Therefore apply beta-decrease on “(λy, y×3)2,“ will return 2 × 3 = 6
Presently the tem becomes, (λf λx f(f(fx)))6
The main term, (λf λx f(f(fx))) takes a capacity and a contention and substitute the contention in the capacity.
Here it is given that it is conceivable to substitute, the subsequent increase in the outcome.
In this way by applying next level beta - decrease, the term becomes f(f(f(6))), which is in ordinary structure.
b. A rigid bar does not bend regardless of the loads acting upon it.
c. A rigid bar deforms when experiencing applied loads.
d. A rigid bar is unable to translate or rotate about a support.
e. A rigid bar represents an object that does not experience deformation of any kind.
Answer:
option b and E are true
Explanation:
A lever is an example of a rigid bar that can rotate around a given point. In a rigid material, the existing distance does not change whenever any load is placed on it. In such a material, there can be no deformation whatsoever. Wit this explanation in mind:
option a is incorrect, given that we already learnt that no deformation of any kind happens in a rigid bar.
option b is true. A rigid bar remains unchanged regardless of the load that it carries.
option c is incorrect, a rigid bar does not deform with loads on it
option d is incorrect. A lever is a type of rigid bar, a rigid bar can rotate around a support.
option e is true. A rigid bar would not experience any deformation whatsoever.
Answer:
Option C..Farmers saught new technology to help with the workload
hope this helped you
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Answer:
(c)- Elastic modulus
Explanation:
We know that in tensile test we measure the properties of the material like yield strength,ultimate tensile strength ,Poisson ratio.
In tensile test
σ = ε E
Where σ is the stress
ε is the strain.
E is the elastic modulus.
Now for shear tress
τ = Φ G
Where τ the shear stress
Φ is the shear strain.
G is the shear modulus.
So we can say that Shear modulus is analogous to Elastic modulus.
Answer:
1 ton refrigeration =3.517 kJ/s = 3.517 kW
Explanation:
Refrigeration capacity is defined at the measure of the effective cooling capacity of a refrigerator which is expressed in Btu per hour or in tons.
1 ton capacity is a unit of air conditioning and refrigeration which measure the capacity of air conditioning and refrigeration unit.
One ton is equal to removal of 3025kcal heat per hour
1 ton refrigeration = 200 Btu/min = 3.517 kJ/s = 3.517 kW = 4.713 HP
Answer:
I = Line Current = 242.58 A
Q = Reactive Power = 41.5 kVAr
Explanation:
Firstly, converting 100 hp to kW.
Since, 1 hp = 0.746 kW,
100 hp = 0.746 kW x 100
100 hp = 74.6 kW
The power of a three phase induction motor can be given as:
where,
P in = Input Power required by the motor
V = Line Voltage
I = Line Current
Cosα = Power Factor
Now, calculating Pin:
a) Calculating the line current:
b) Calculating Reactive Power:
The reactive power can be calculated as:
Q = P tanα
where,
Q = Reactive power
P = Active Power
α = power factor angle
Since,
Therefore,