Answer:
T = 858.25 s
Explanation:
Given data:
Reheat stage for a 100-mm-thick steel plate ( 7830 kg/m3, c 550 J/kg K, k 48 W/m K),
initial uniform temperature ( Ti ) = 200 c
Final temperature = 550 c
convection coefficient = 250 w/m^2 k
products combustion temp = 800 c
calculate how long the plate should be left in the furnace ( to attain 550 c )
first calculate/determine the Fourier series Number ( Fo )
= 0.4167 =
therefore Fo = 3.8264
Now determine how long the plate should be left in the furnace
Fo =
k = 48
p = 7830
L = 0.1
Input the values into the relation and make t subject of the formula
hence t = 858.25 s
Answer:
the netuon arrangment
Explanation:
B. Either vertically or horizontally polarized antennas may be used for transmission or reception
C. FM voice is unusable
D. Both the transmitting and receiving antennas must be of the same polarization
Answer:
B
Explanation:
The fact that skip signals refracted from the ionosphere are elliptically polarized is a result of either vertically or horizontally polarized antennas may be used for transmission or reception.
B. isolation joints
C. control joints
D. construction joints
If you are pouring a large concrete slab and wish to avoid random cracks caused by shrinkage, you would likely provide Control joints. The correct answer would be C.
Control joints are used to prevent random cracks from forming in large concrete slabs caused by shrinkage. These joints are placed at strategic locations in the slab to allow for the concrete to expand and contract without cracking. Expansion joints, on the other hand, are used to separate concrete from other structures or materials, and isolation joints are used to separate different sections of concrete.
Construction joints are used to connect two different pours of concrete. Therefore, the best option for preventing random cracks caused by shrinkage would be to use control joints.
Learn more about Control joints:
#SPJ11
Answer:
voltage across the capacitor's is 75 μF
Explanation:
given data
capacitor = 15 μF
voltage = 50V
dielectric constant k = 5
to find out
voltage across the capacitor's
solution
we will find here voltage across the capacitor's by this formula
voltage across the capacitor's = k
here k is 5 and = 15
put these value we get
voltage across the capacitor's = k
voltage across the capacitor's = 5 ( 15 ) = 75 μF
so voltage across the capacitor's is 75 μF
Answer:
BOD_5 = =65.8 mg/l
Explanation:
dilution water DO level = 0.8 m/l
BOD level drop to 7.3 mg/l
we know that BOD at 5th day can be clculated by using following relation
- DO drop in BOD bottle
- dilution water drop
P= 30/300 = 0.1
(b) 75 kHz
(c) 80 kHz
(d) 160 kHz
(e) None of the above.
Answer:
Option D
160 kHz
Explanation:
Since we must use at least one synchronization bit, total message signal is 15+1=16
The minimum sampling frequency, fs=2fm=2(5)=10 kHz
Bandwith, BW required is given by
BW=Nfs=16(10)=160 kHz