In amino acid "valine", the terminal groups attach with what atom?

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Leutium-176 has a half-life of 3.85 mc012-1.jpg 1010 years. After 1.155 mc012-2.jpg 1011 years, how much leutium-176 will remain from an original 16.8-g sample?2.10 g
3.00 g
5.56 g
8.40 g

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Answer : The amount left of leutium-176 will be, 2.10 g

Solution :

First we have to calculate the rate constant, we use the formula :

$k=(0.693)/(t_(1/2))$

$k=\frac{0.693}{3.85* 10^(10)\text{years}}$

$k=0.18* 10^(-10)\text{years}^(-1)$

Now we have to calculate the amount left of the sample.

Expression for rate law for first order kinetics is given by :

$t=(2.303)/(k)\log(a)/(a-x)$

where,

k = rate constant = $0.18* 10^(-10)\text{years}^(-1)$

t = decay time = $1.155* 10^(11)\text{ years}$

a = initial amount of the sample = 16.8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1.155* 10^(11)\text{years}=\frac{2.303}{0.18* 10^(-10)\text{years}^(-1)}\log(16.8)/(a-x)$

$a-x=2.10g$

Therefore, the amount left of leutium-176 will be, 2.10 g

Answer:

Explanation:

The closeness of a measurement to the actual value of what is being measured

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Hey!

This is known accuracy. Think of accuracy as like shooting at the bulls eye on a target.

However think of precision like if all your darts fell on the lower left side of the target. Precision is just how close together the measurements are with each other.

The Tacoma narrows bridge collapsed due to?A. Refraction
B. Reflection
C. Diffraction
D. Resonance

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D. Resonance. the bridge was driven at its resonant frequency

A buffer contains the weak acid HA and its conjugate base A-. the weak acid has a p Ka of 4.82 and the buffer has a pH of 4.25. Which statement is true of the relative concentration of the weak acid and its conjugate base in the buffer? a) [HA} > [A-]
b) [Ha} < [A-]
c) [HA]=[A-]

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I think the correct answer is A. A buffer is a substance that resists small change in the acidity of a solution when an acid or base is added to the solution. Usually, a buffer involves a weak acid or a weak alkali and one of its salt.

2. Based on what you know about waves and light, do you think that light can bemodeled as a wave? Explain why or why not.

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Answer:

Light as a wave: Light can be described (modeled) as an electromagnetic wave. In this model, a changing electric field creates a changing magnetic field. This changing magnetic field then creates a changing electric field and BOOM - you have light. ... So, Maxwell's equations do say that light is a wave.

Explanation:

Hope this helps

Answer:

Explanation:

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In a coffee-cup calorimeter, 100.0 ml of 1.0 m naoh and 100.0 ml of 1.0 m hcl are mixed. both solutions were originally at 24.68c. after the reaction, the final temperature is 31.38c. assuming that all the solutions have a density of 1.0 g/cm3 and a specific heat capacity of 4.18 j/8c ? g, calculate the enthalpy change for the neutralization of hcl by naoh

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The enthalpy change (ΔH) for the neutralization of 0.1 moles of 1.0 M NaOH with 0.1 moles of 1.0 M HCl in a coffee-cup calorimeter is approximately 28.05 kJ/mol.

To calculate the enthalpy change (ΔH) for the neutralization of HCl by NaOH, you can use the equation:

ΔH = q / moles of limiting reactant

First, let's find the moles of the reactants. We have 100.0 mL of 1.0 M NaOH and 100.0 mL of 1.0 M HCl. Since we know the volumes and concentrations, you can find the moles of each reactant using the formula:

moles = (volume in L) × (concentration in mol/L)

For NaOH:

moles of NaOH = (100.0 mL / 1000 mL/L) × 1.0 mol/L = 0.1 moles

For HCl:

moles of HCl = (100.0 mL / 1000 mL/L) × 1.0 mol/L = 0.1 moles

Now, you need to determine the limiting reactant. The balanced chemical equation for the neutralization of HCl by NaOH is:

NaOH + HCl → NaCl + H₂O

The stoichiometric ratio of NaOH to HCl is 1:1, which means they react in a 1:1 ratio. Since both reactants have 0.1 moles, neither is in excess. Therefore, the reactant that limits the reaction is the one that is present in the smaller amount, which is NaOH in this case.

Now, calculate the heat absorbed or released (q) using the equation:

q = mΔTC

Where:

m is the mass (in grams) of the solution, which we can calculate using the density of 1.0 g/cm³ and the volume (in mL).

ΔT is the change in temperature.

C is the specific heat capacity (given as 4.18 J/g°C).

For the volume of 100.0 mL, the mass is 100.0 g (since 100.0 mL = 100.0 g, given the density is 1.0 g/cm³).

ΔT = Final temperature - Initial temperature

ΔT = 31.38°C - 24.68°C = 6.70°C

Now, calculate q for the reaction:

q = 100.0 g × 6.70°C × 4.18 J/g°C = 2804.76 J

Finally, calculate the enthalpy change (ΔH) by dividing q by the moles of the limiting reactant:

ΔH = 2804.76 J / 0.1 moles = 28047.6 J/mol

Since the enthalpy change is typically expressed in kJ/mol, divide by 1000 to convert J to kJ:

ΔH = 28.05 kJ/mol

So, the enthalpy change for the neutralization of HCl by NaOH is approximately 28.05 kJ/mol.

To know more about moles:

brainly.com/question/34302357

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