Answer:
a)Q=131.1 MJ
b)Q=54 MJ
Explanation:
Given that
Mass ,m=200 kg
Specific heat Cp=0.46 J/g°C
Cp=0.46 KJ/kg°C
Heat of fusion = 270 J/g
Heat of fusion = 270 KJ/kg
Melting point temperature = 1450°C
a)
Initial temperature = 25°C
Final temperature=1450°C
Heat required to rise temperature from 25°C to 1450°C.
Q= m CpΔT
Q=200 x 0.46 x (1450-25) KJ
Q=131,100 KJ
Q=131.1 MJ
b)
Heat required to transform from solid phase to liquid phase
Q= Mass x heat of fusion
Q=200 x 27 KJ
Q=54,000 KJ
Q=54 MJ
Fluorescent lamps
Mercury-containing lamps
All of the above
Answer: D all above
Explanation:
Jus done it
Answer:
True
Explanation:
For steels, we can assume the endurance limit measured by rotating beam tests is the 50% of the ultimate tensile strength (UTS) as long as the UTS is equal to or less than 200 kpsi (1400 MPa).
Also, It is a simplistic rule of thumb that, for steels having a UTS less than 160 kpsi, the endurance limit for the material will be approximately 45 to 50% of the UTS.
Answer:
Too many question marks
Explanation:
again = "false";
result = 0;
a. choice
b. again
c. result
d. none of these are Boolean variables
Answer:
C
Explanation:
Boolean Algebra deals with either a one or a zero and how to manipulate them in computers or elsewhere. The "choice" option may not work, since for text it must be enclosed in quotation marks, usually. For "again," it's text and not a 1 or 0. So, the answer is C, since this is a 0.
Here’s an example of program use
Input the first number: 10
Input the second number: 5
The maximum value is 10
Run again? yes
Input the first number: -10
Input the second number: -5
The maximum value is -5
Run again? no
Function max():
Obtain two numbers as input parameters: max(num1, num2):
if num1 > num2 max_val = num1, else max_val = num2
return max_val
Main Program:
Initialize loop control variable (continue = ‘y’)
While continue == ‘y’
Prompt for first number
Prompt for second number
Call function "max," sending it the values of the two numbers, capture result in an assignment statement:
max_value = max (n1, n2)
Display the maximum value returned by the function
print(‘Max =’, max_val)
Ask user for if she/he wants to continue (continue = input(‘Go again? y if yes’)
A loop is a control structure in programming that allows a block of code to be executed repeatedly.
Here is the Python code that implements the function and program described in the question:
def max(num1, num2):
if num1 > num2:
max_val = num1
else:
max_val = num2
return max_val
# Main program
continue = 'y'
while continue == 'y':
n1 = int(input("Input the first number: "))
n2 = int(input("Input the second number: "))
max_val = max(n1, n2)
print("The maximum value is", max_val)
continue = input("Run again? ")
Loops are an important programming construct that allow you to perform the same task multiple times with minimal code. They are often used to process data, perform calculations, and perform repetitive tasks.
To Know More About Loops, Check Out
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