What is the answer What two totally normal things become really weird if you do them back to back?

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Answer 1
Answer:

Answer: i like the way you scream


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A 24.3-foot long pipe use to carry solvent through a chemical plant is made of two layers. The inner layer is a one-inch schedule 30 stainless steel (AISI 304) pipe. An outer coating is made of plain carbon steel and is 0.075 inches thick. The hot solvent stream can be assumed to have a constant temperature of 180.0oF as it passes through the pipe. On the outside of the pipe is air at 85.0oF. Given the solvent has a convective heat transfer coefficient of 275 Btu/h-ft^2-oF, while the air has a convective heat transfer coefficient of 140 Btu/h-ft^2-oF.A. Determine UA and q for heat transfer in this system. (Since the problem is given in English units, your answer should also be in English units)
B. Determine the overall heat transfer coefficients, U; and U., for the pipe.
C. Would your answer change if the two materials were swapped so that the inside material were carbon steel and the outside material of the pipe were made of AISI 304 stainless steel? If so, calculate new values for UA and q. If not, explain why your answer would not change. (Here, assume the dimensions of the inner material (now plain carbon steel) match those of the AISI 304 schedule 30 stainless steel from part A, and the stainless steel is 0.075 inches thick on the outside.)

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Sorry man i dont know the answer to this one

1. An automobile travels along a straight road at 15.65 m/s through a 11.18 m/sspeed zone. A police car observed the automobile. At the instant that the two
vehicles are abreast of each other, the police car starts to pursue the automobile at
a constant acceleration of 1.96 m/s². The motorist noticed the police car in his rear
view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s². (Hint: The police will not go against the law.)
a) Find the total time required for the police car to overtake the automobile.
b) Find the total distance travelled by the police car while overtaking the
automobile.
c) Find the speed of the police car at the time it overtakes the automobile.
d) Find the speed of the automobile at the time it was overtaken by the police car.

Answers

Answer:

a.) Time = 17.13 seconds

b.) 31.88 m

c.) V = 11.18 m/s

d.) V = 7.1 m/s

Explanation:

The initial velocity U of the automobile is 15.65 m/s.

 At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.

For the automobile, let us use first equation of motion

V = U - at.

Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And

V = 0.

Substitute U and a into the formula

0 = 15.65 - 3.05t

15.65 = 3.05t

t = 15.65/3.05

t = 5.13 seconds

But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².

The total time required for the police car to overtake the automobile will be

12 + 5.13 = 17.13 seconds.

b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²

V^2 = U^2 + 2aS

Where S = distance travelled.

Substitute V and a into the formula

11.18^2 = 0 + 2 × 1.96 ×S

124.99 = 3.92S

S = 124.99/3.92

S = 31.88 m

c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s

d.) That will be the final velocity V of the automobile car.

We will use third equation of motion to solve that.

V^2 = U^2 + 2as

V^2 = 15.65^2 - 2 × 3.05 × 31.88

V^2 = 244.9225 - 194.468

V = sqrt( 50.4545)

V = 7.1 m/s

Make a python code.Write a function named max that accepts two integer values as arguments and returns the value that is the greater of the two. For example, if 7 and 12 are passed as arguments to the function, the function should return 12. Use the function in a program that prompts the user to enter two integer values. The program should display the value that is the greater of the two. Write the program as a loop that continues to prompt for two numbers, outputs the maximum, and then goes back and prompts again
Here’s an example of program use
Input the first number: 10
Input the second number: 5
The maximum value is 10
Run again? yes
Input the first number: -10
Input the second number: -5
The maximum value is -5
Run again? no
Function max():
Obtain two numbers as input parameters: max(num1, num2):
if num1 > num2 max_val = num1, else max_val = num2
return max_val
Main Program:
Initialize loop control variable (continue = ‘y’)
While continue == ‘y’
Prompt for first number
Prompt for second number
Call function "max," sending it the values of the two numbers, capture result in an assignment statement:
max_value = max (n1, n2)
Display the maximum value returned by the function
print(‘Max =’, max_val)
Ask user for if she/he wants to continue (continue = input(‘Go again? y if yes’)

Answers

A loop is a control structure in programming that allows a block of code to be executed repeatedly.

How to write the python code?

Here is the Python code that implements the function and program described in the question:

def max(num1, num2):

 if num1 > num2:

   max_val = num1

 else:

   max_val = num2

 return max_val

# Main program

continue = 'y'

while continue == 'y':

 n1 = int(input("Input the first number: "))

 n2 = int(input("Input the second number: "))

 max_val = max(n1, n2)

 print("The maximum value is", max_val)

 continue = input("Run again? ")

Loops are an important programming construct that allow you to perform the same task multiple times with minimal code. They are often used to process data, perform calculations, and perform repetitive tasks.

To Know More About Loops, Check Out

brainly.com/question/29313454

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One piece of evidence that supports the Theory of Plate Tectonics is the discovery of what in both South America and Africa? The ancient atmosphere in both places was identical. The rates of weathering of rock are similar. Fossil remains of the same land-dwelling animal. Plants on both continents have similar flowers.

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Answer: Fossil remains of the same land-dwelling animal.

Explanation: Fossil remains which were found to belong to same land dwelling animals, in South America and Africa was used as evidence to help support the theory of Tectonics plates, what this theory simply means is that the whole continents of earth were once fused together until a tectonic plate caused it’s division. Since same remains were found in Africa and South America this shows that both continents were once fused together.

Answer:

Fossil remains of the same land-dwelling animal

Explanation:

Fossil remains tell us where the animals once lived and how by the movement of plate spearated their remaind that was burried thousands of years ago.

An inventor claims that he wants to build a dam to produce hydroelectric power. He correctly realizes that civilization uses a lot more electricity during the day than at night, so he thinks he has stumbled upon a great untapped energy supply. His plan is to install pumps at the bottom of the dam so that he can pump some of the water that flows out from the generators back up into the reservoir using the excess electricity generated at night. He reasons that if he did that, the water would just flow right back down through the generators the next day producing power for free. What is wrong with his plan?

Answers

Answer:

The problem is that the pumps would consume more energy than the generators would produce.

Explanation:

Water has a potential energy associated with the height it is at. The higher it is, the higher the potential energy. When water flows down into the turbines that energy is converted to kinetic energy and then into electricity.

A pump uses electricity to add energy to the water to send it to a higher potential energy state.

Ideally no net energy woul be hgenerate or lost, because the generators would release the potential energy and pumps would store it again in the water. However the systems are not ideal, everything has an efficiency and losses. The losses would accumulate and the generator would be generating less energy than the pumps consume, so that system wastes energy.

What should be done is closing the floodgates to keep the water up in the dam at night producing only the power that is needed and releasing more water during the day.

The information on a can of pop indicates that the can contains 360 mL. The mass of a full can of pop is 0.369 kg, while an empty can weighs 0.153 N. Determine the specific weight, density, and specific gravity of the pop and compare your results with the corresponding values for water at Express your results in SI units.

Answers

Answer:

Specific weight of the pop, w_(s) = 8619.45 N/m^(3)

Density of the pop, \rho_(p) = 8790.76 kg/m^(3)

g_(s) = 8.79076

w_(w) = 9782.36 N/m^(3)

Given:

Volume of pop, V = 360 mL = 0.36 L = 0.36* 10^(-3) m^(3)

Mass of a can of pop , m = 0.369 kg

Weight of an empty can, W = 0.153 N

Solution:

Now, weight of a full can pop, W

W' = mg = 0.369* 9.8 = 3.616 N

Now weight of the pop in can is given by:

w = W' - W = 3.616 - 0.513 = 3.103 N

Now,

The specific weight of the pop, w_(s) = (weight of pop)/(volume of pop)

w_(s) = (3.103)/(0.36* 10^(- 3)) = 8619.45 N/m^(3)

Now, density of the pop:

\rho_(p) = (w_(s))/(g)

\rho_(p) = (86149.45)/(9.8) = 8790.76 kg/m^(3)

Now,

Specific gravity, g_(s) = (\rho_(p))/(density of water, \rho_(w))

where

g_(s) = (8790.76)/(1000) = 8.79076

Now, for water at 20^(\circ)c:

Specific density of water = 998.2 kg/m^(3)

Specific gravity of water = 0.998 kg/m^(3)

Specific weight of water at 20^(\circ)c:

w_(w) = \rho_(20^(\circ))* g = 998.2* 9.8 = 9782.36 N/m^(3)

Other Questions
IN JAVA,Knapsack ProblemThe file KnapsackData1.txt and KnapsackData2.txt are sample input filesfor the following Knapsack Problem that you will solve.KnapsackData1.txt contains a list of four prospective projects for the upcoming year for a particularcompany:Project0 6 30Project1 3 14Project2 4 16Project3 2 9Each line in the file provides three pieces of information:1) String: The name of the project;2) Integer: The amount of employee labor that will be demanded by the project, measured in work weeks;3) Integer: The net profit that the company can expect from engaging in the project, measured in thousandsof dollars.Your task is to write a program that:1) Prompts the user for the number of work weeks available (integer);2) Prompts the user for the name of the input file (string);3) Prompts the user for the name of the output file (string);4) Reads the available projects from the input file;5) Dolves the corresponding knapsack problem, without repetition of items; and6) Writes to the output file a summary of the results, including the expected profit and a list of the bestprojects for the company to undertake.Here is a sample session with the program:Enter the number of available employee work weeks: 10Enter the name of input file: KnapsackData1.txtEnter the name of output file: Output1.txtNumber of projects = 4DoneFor the above example, here is the output that should be written to Output1.txt:Number of projects available: 4Available employee work weeks: 10Number of projects chosen: 2Number of projectsTotal profit: 46Project0 6 30Project2 4 16The file KnapsackData2.txt, contains one thousand prospective projects. Your program should also be able to handle this larger problem as well. The corresponding output file,WardOutput2.txt, is below.With a thousand prospective projects to consider, it will be impossible for your program to finish in areasonable amount of time if it uses a "brute-force search" that explicitly considers every possiblecombination of projects. You are required to use a dynamic programming approach to this problem.WardOutput2.txt:Number of projects available: 1000Available employee work weeks: 100Number of projects chosen: 66Total profit: 16096Project15 2 236Project73 3 397Project90 2 302Project114 1 139Project117 1 158Project153 3 354Project161 2 344Project181 1 140Project211 1 191Project213 2 268Project214 2 386Project254 1 170Project257 4 427Project274 1 148Project275 1 212Project281 2 414Project290 1 215Project306 2 455Project334 3 339Project346 2 215Project356 3 337Project363 1 159Project377 1 105Project389 1 142Project397 1 321Project399 1 351Project407 3 340Project414 1 266Project431 1 114Project435 3 382Project446 1 139Project452 1 127Project456 1 229Project461 1 319Project478 1 158Project482 2 273Project492 1 142Project525 1 144Project531 1 382Project574 1 170Project594 1 125Project636 2 345Project644 1 169Project668 1 191Project676 1 117Project684 1 143Project689 1 108Project690 1 216Project713 1 367Project724 1 127Project729 2 239Project738 1 252Project779 1 115Project791 1 110Project818 2 434Project820 1 222Project830 1 179Project888 3 381Project934 3 461Project939 3 358Project951 1 165Project959 2 351Project962 1 316Project967 1 191Project984 1 117Project997 1 187