Answer: i like the way you scream
B. Determine the overall heat transfer coefficients, U; and U., for the pipe.
C. Would your answer change if the two materials were swapped so that the inside material were carbon steel and the outside material of the pipe were made of AISI 304 stainless steel? If so, calculate new values for UA and q. If not, explain why your answer would not change. (Here, assume the dimensions of the inner material (now plain carbon steel) match those of the AISI 304 schedule 30 stainless steel from part A, and the stainless steel is 0.075 inches thick on the outside.)
Sorry man i dont know the answer to this one
vehicles are abreast of each other, the police car starts to pursue the automobile at
a constant acceleration of 1.96 m/s². The motorist noticed the police car in his rear
view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s². (Hint: The police will not go against the law.)
a) Find the total time required for the police car to overtake the automobile.
b) Find the total distance travelled by the police car while overtaking the
automobile.
c) Find the speed of the police car at the time it overtakes the automobile.
d) Find the speed of the automobile at the time it was overtaken by the police car.
Answer:
a.) Time = 17.13 seconds
b.) 31.88 m
c.) V = 11.18 m/s
d.) V = 7.1 m/s
Explanation:
The initial velocity U of the automobile is 15.65 m/s.
At the instant that the two vehicles are abreast of each other, the police car starts to pursue the automobile with initial velocity U = 0 at a constant acceleration of 1.96 m/s². Because the police is starting from rest.
For the automobile, let us use first equation of motion
V = U - at.
Acceleration a is negative since it is decelerating with a = 3.05 m/s² . And
V = 0.
Substitute U and a into the formula
0 = 15.65 - 3.05t
15.65 = 3.05t
t = 15.65/3.05
t = 5.13 seconds
But the motorist noticed the police car in his rear view mirror 12 s after the police car started the pursuit and applied his brakes and decelerates at 3.05 m/s².
The total time required for the police car to overtake the automobile will be
12 + 5.13 = 17.13 seconds.
b.) Using the third equation of motion formula for the police car at V = 11.18 m/s and a = 1.96 m/s²
V^2 = U^2 + 2aS
Where S = distance travelled.
Substitute V and a into the formula
11.18^2 = 0 + 2 × 1.96 ×S
124.99 = 3.92S
S = 124.99/3.92
S = 31.88 m
c.) The speed of the police car at the time it overtakes the automobile will be in line with the speed zone which is 11.18 m/s
d.) That will be the final velocity V of the automobile car.
We will use third equation of motion to solve that.
V^2 = U^2 + 2as
V^2 = 15.65^2 - 2 × 3.05 × 31.88
V^2 = 244.9225 - 194.468
V = sqrt( 50.4545)
V = 7.1 m/s
Here’s an example of program use
Input the first number: 10
Input the second number: 5
The maximum value is 10
Run again? yes
Input the first number: -10
Input the second number: -5
The maximum value is -5
Run again? no
Function max():
Obtain two numbers as input parameters: max(num1, num2):
if num1 > num2 max_val = num1, else max_val = num2
return max_val
Main Program:
Initialize loop control variable (continue = ‘y’)
While continue == ‘y’
Prompt for first number
Prompt for second number
Call function "max," sending it the values of the two numbers, capture result in an assignment statement:
max_value = max (n1, n2)
Display the maximum value returned by the function
print(‘Max =’, max_val)
Ask user for if she/he wants to continue (continue = input(‘Go again? y if yes’)
A loop is a control structure in programming that allows a block of code to be executed repeatedly.
Here is the Python code that implements the function and program described in the question:
def max(num1, num2):
if num1 > num2:
max_val = num1
else:
max_val = num2
return max_val
# Main program
continue = 'y'
while continue == 'y':
n1 = int(input("Input the first number: "))
n2 = int(input("Input the second number: "))
max_val = max(n1, n2)
print("The maximum value is", max_val)
continue = input("Run again? ")
Loops are an important programming construct that allow you to perform the same task multiple times with minimal code. They are often used to process data, perform calculations, and perform repetitive tasks.
To Know More About Loops, Check Out
#SPJ4
Answer: Fossil remains of the same land-dwelling animal.
Explanation: Fossil remains which were found to belong to same land dwelling animals, in South America and Africa was used as evidence to help support the theory of Tectonics plates, what this theory simply means is that the whole continents of earth were once fused together until a tectonic plate caused it’s division. Since same remains were found in Africa and South America this shows that both continents were once fused together.
Answer:
Fossil remains of the same land-dwelling animal
Explanation:
Fossil remains tell us where the animals once lived and how by the movement of plate spearated their remaind that was burried thousands of years ago.
Answer:
The problem is that the pumps would consume more energy than the generators would produce.
Explanation:
Water has a potential energy associated with the height it is at. The higher it is, the higher the potential energy. When water flows down into the turbines that energy is converted to kinetic energy and then into electricity.
A pump uses electricity to add energy to the water to send it to a higher potential energy state.
Ideally no net energy woul be hgenerate or lost, because the generators would release the potential energy and pumps would store it again in the water. However the systems are not ideal, everything has an efficiency and losses. The losses would accumulate and the generator would be generating less energy than the pumps consume, so that system wastes energy.
What should be done is closing the floodgates to keep the water up in the dam at night producing only the power that is needed and releasing more water during the day.
Answer:
Specific weight of the pop,
Density of the pop,
Given:
Volume of pop, V = 360 mL = 0.36 L =
Mass of a can of pop , m = 0.369 kg
Weight of an empty can, W = 0.153 N
Solution:
Now, weight of a full can pop, W
W' = mg =
Now weight of the pop in can is given by:
w = W' - W = 3.616 - 0.513 = 3.103 N
Now,
The specific weight of the pop,
Now, density of the pop:
Now,
Specific gravity,
where
Now, for water at :
Specific density of water =
Specific gravity of water =
Specific weight of water at :